Distance between 
Winnambool and 
Sebastopol
272.15 mi Straight Distance
332.68 mi Driving Distance
6 hours 41 mins Estimated Driving Time
The straight distance between Winnambool (Victoria) and Sebastopol (New South Wales) is 272.15 mi, but the driving distance is 332.68 mi.
It takes 6 hours 41 mins to go from Winnambool to Sebastopol.
Driving directions from Winnambool to Sebastopol
Distance in kilometers
Straight distance: 437.88 km. Route distance: 535.29 km
Winnambool, Australia
Latitude: -34.958 // Longitude: 142.748
Photos of Winnambool
Winnambool Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Sun info not available
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Sun info not available
