Distance between 
Winnambool and 
Sebastopol
272.15 mi Straight Distance
332.68 mi Driving Distance
6 hours 41 mins Estimated Driving Time
The straight distance between Winnambool (Victoria) and Sebastopol (New South Wales) is 272.15 mi, but the driving distance is 332.68 mi.
It takes to go from Winnambool to Sebastopol.
Driving directions from Winnambool to Sebastopol
Distance in kilometers
Straight distance: 437.88 km. Route distance: 535.29 km
Winnambool, Australia
Latitude: -34.958 // Longitude: 142.748
Photos of Winnambool
Winnambool Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 08:18 PM
Sunset: 09:03 AM
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 07:59 PM
Sunset: 08:43 AM
