282.24 mi Straight Distance
365.02 mi Driving Distance
7 hours 8 mins Estimated Driving Time
The straight distance between Wallace (Victoria) and Sebastopol (New South Wales) is 282.24 mi, but the driving distance is 365.02 mi.
It takes to go from Wallace to Sebastopol.
Driving directions from Wallace to Sebastopol
Straight distance: 454.12 km. Route distance: 587.31 km
Latitude: -37.555 // Longitude: 144.051

Forecast: Scattered clouds
Temperature: 11.6°
Humidity: 93%
Current time: 08:41 AM
Sunrise: 06:55 AM
Sunset: 08:20 PM
Latitude: -34.5851 // Longitude: 147.522

Forecast: Few clouds
Temperature: 23.3°
Humidity: 41%
Current time: 10:00 AM
Sunrise: 06:45 AM
Sunset: 08:02 PM