Distance between 
Sebastopol and 
Winnambool
272.15 mi Straight Distance
332.72 mi Driving Distance
6 hours 41 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Winnambool (Victoria) is 272.15 mi, but the driving distance is 332.72 mi.
It takes 6 hours 41 mins to go from Sebastopol to Winnambool.
Driving directions from Sebastopol to Winnambool
Distance in kilometers
Straight distance: 437.88 km. Route distance: 535.35 km
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Sun info not available
Winnambool, Australia
Latitude: -34.958 // Longitude: 142.748
Photos of Winnambool
Winnambool Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Sun info not available
