Distance between 
Sebastopol and 
Winnambool
272.15 mi Straight Distance
332.72 mi Driving Distance
6 hours 41 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Winnambool (Victoria) is 272.15 mi, but the driving distance is 332.72 mi.
It takes to go from Sebastopol to Winnambool.
Driving directions from Sebastopol to Winnambool
Distance in kilometers
Straight distance: 437.88 km. Route distance: 535.35 km
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 07:58 PM
Sunset: 08:45 AM
Winnambool, Australia
Latitude: -34.958 // Longitude: 142.748
Photos of Winnambool
Winnambool Weather
Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 08:17 PM
Sunset: 09:04 AM
