282.24 mi Straight Distance
362.22 mi Driving Distance
7 hours 8 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Wallace (Victoria) is 282.24 mi, but the driving distance is 362.22 mi.
It takes to go from Sebastopol to Wallace.
Driving directions from Sebastopol to Wallace
Straight distance: 454.12 km. Route distance: 582.81 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Clear sky
Temperature: 29.7°
Humidity: 26%
Current time: 12:00 AM
Sunrise: 07:44 PM
Sunset: 09:03 AM
Latitude: -37.555 // Longitude: 144.051

Forecast: Scattered clouds
Temperature: 30.0°
Humidity: 34%
Current time: 03:27 PM
Sunrise: 06:54 AM
Sunset: 08:21 PM