298.06 mi Straight Distance
382.20 mi Driving Distance
7 hours 37 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Nintingbool (Victoria) is 298.06 mi, but the driving distance is 382.20 mi.
It takes 9 mins to go from Sebastopol to Nintingbool.
Driving directions from Sebastopol to Nintingbool
Straight distance: 479.58 km. Route distance: 614.97 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Broken clouds
Temperature: 22.6°
Humidity: 34%
Current time: 12:00 AM
Sunrise: 07:42 PM
Sunset: 09:05 AM
Latitude: -37.6149 // Longitude: 143.72

Forecast: Few clouds
Temperature: 22.2°
Humidity: 62%
Current time: 08:45 PM
Sunrise: 06:53 AM
Sunset: 08:25 PM