Distance between 
Sebastopol and 
Mount Prospect
274.77 mi Straight Distance
341.49 mi Driving Distance
7 hours 7 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Mount Prospect (Victoria) is 274.77 mi, but the driving distance is 341.49 mi.
It takes 32 mins to go from Sebastopol to Mount Prospect.
Driving directions from Sebastopol to Mount Prospect
Distance in kilometers
Straight distance: 442.10 km. Route distance: 549.45 km
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 21.5°
Humidity: 70%
Current time: 12:00 AM
Sunrise: 07:51 PM
Sunset: 08:55 AM
Mount Prospect, Australia
Latitude: -37.3892 // Longitude: 144.036
Photos of Mount Prospect
Mount Prospect Weather
Forecast: Overcast clouds
Temperature: 17.8°
Humidity: 73%
Current time: 12:00 AM
Sunrise: 08:02 PM
Sunset: 09:12 AM
