266.58 mi Straight Distance
334.06 mi Driving Distance
7 hours 9 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Logan (Victoria) is 266.58 mi, but the driving distance is 334.06 mi.
It takes to go from Sebastopol to Logan.
Driving directions from Sebastopol to Logan
Straight distance: 428.93 km. Route distance: 537.50 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Clear sky
Temperature: 23.8°
Humidity: 23%
Current time: 12:00 AM
Sunrise: 07:45 PM
Sunset: 09:02 AM
Latitude: -36.622 // Longitude: 143.491

Forecast: Clear sky
Temperature: 20.5°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 07:58 PM
Sunset: 09:20 AM