197.92 mi Straight Distance
236.76 mi Driving Distance
4 hours 42 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Locksley (Victoria) is 197.92 mi, but the driving distance is 236.76 mi.
It takes to go from Sebastopol to Locksley.
Driving directions from Sebastopol to Locksley
Straight distance: 318.45 km. Route distance: 380.94 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Few clouds
Temperature: 23.3°
Humidity: 41%
Current time: 12:00 AM
Sunrise: 07:44 PM
Sunset: 09:03 AM
Latitude: -36.8336 // Longitude: 145.336

Forecast: Overcast clouds
Temperature: 15.4°
Humidity: 87%
Current time: 12:00 AM
Sunrise: 07:50 PM
Sunset: 09:15 AM