288.15 mi Straight Distance
377.63 mi Driving Distance
7 hours 31 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Lascelles (Victoria) is 288.15 mi, but the driving distance is 377.63 mi.
It takes to go from Sebastopol to Lascelles.
Driving directions from Sebastopol to Lascelles
Straight distance: 463.63 km. Route distance: 607.60 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 07:59 PM
Sunset: 08:43 AM
Latitude: -35.6085 // Longitude: 142.58

Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 08:18 PM
Sunset: 09:04 AM