Distance between 
Sebastopol and 
Langley
244.84 mi Straight Distance
307.31 mi Driving Distance
6 hours 11 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Langley (Victoria) is 244.84 mi, but the driving distance is 307.31 mi.
It takes 1 hour 19 mins to go from Sebastopol to Langley.
Driving directions from Sebastopol to Langley
Distance in kilometers
Straight distance: 393.94 km. Route distance: 494.47 km
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 21.4°
Humidity: 40%
Sun info not available
Langley, Australia
Latitude: -37.1507 // Longitude: 144.505
Photos of Langley
Langley Weather
Forecast: Clear sky
Temperature: 17.7°
Humidity: 71%
Sun info not available
