272.86 mi Straight Distance
338.55 mi Driving Distance
7 hours 9 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Jeffcott (Victoria) is 272.86 mi, but the driving distance is 338.55 mi.
It takes to go from Sebastopol to Jeffcott.
Driving directions from Sebastopol to Jeffcott
Straight distance: 439.03 km. Route distance: 544.73 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Clear sky
Temperature: 33.5°
Humidity: 9%
Current time: 12:00 AM
Sunrise: 07:48 PM
Sunset: 08:58 AM
Latitude: -36.2753 // Longitude: 143.141

Forecast: Overcast clouds
Temperature: 33.5°
Humidity: 14%
Current time: 12:00 AM
Sunrise: 08:03 PM
Sunset: 09:18 AM