Distance between 
Sebastopol and 
Framlingham
368.08 mi Straight Distance
460.57 mi Driving Distance
9 hours 20 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Framlingham (Victoria) is 368.08 mi, but the driving distance is 460.57 mi.
It takes to go from Sebastopol to Framlingham.
Driving directions from Sebastopol to Framlingham
Distance in kilometers
Straight distance: 592.23 km. Route distance: 741.06 km
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Few clouds
Temperature: 23.3°
Humidity: 41%
Current time: 12:00 AM
Sunrise: 07:44 PM
Sunset: 09:03 AM
Framlingham, Australia
Latitude: -38.2414 // Longitude: 142.705
Photos of Framlingham
Framlingham Weather
Forecast: Clear sky
Temperature: 11.8°
Humidity: 100%
Current time: 12:00 AM
Sunrise: 07:58 PM
Sunset: 09:27 AM
