240.29 mi Straight Distance
318.40 mi Driving Distance
7 hours 32 mins Estimated Driving Time
The straight distance between Sebastopol (New South Wales) and Clydebank (Victoria) is 240.29 mi, but the driving distance is 318.40 mi.
It takes to go from Sebastopol to Clydebank.
Driving directions from Sebastopol to Clydebank
Straight distance: 386.63 km. Route distance: 512.30 km
Latitude: -34.5851 // Longitude: 147.522

Forecast: Scattered clouds
Temperature: 26.1°
Humidity: 40%
Current time: 12:00 AM
Sunrise: 07:50 PM
Sunset: 08:56 AM
Latitude: -38.053 // Longitude: 147.197

Forecast: Clear sky
Temperature: 15.6°
Humidity: 83%
Current time: 12:00 AM
Sunrise: 07:47 PM
Sunset: 09:01 AM