668.88 mi Straight Distance
803.89 mi Driving Distance
16 hours 28 mins Estimated Driving Time
The straight distance between Sandy Flat (New South Wales) and Seymour (Victoria) is 668.88 mi, but the driving distance is 803.89 mi.
It takes to go from Sandy Flat to Seymour.
Driving directions from Sandy Flat to Seymour
Straight distance: 1,076.22 km. Route distance: 1,293.47 km
Latitude: -29.2312 // Longitude: 152.008

Forecast: Light rain
Temperature: 26.8°
Humidity: 47%
Current time: 12:00 AM
Sunrise: 07:34 PM
Sunset: 08:36 AM
Latitude: -37.0245 // Longitude: 145.137

Forecast: Clear sky
Temperature: 24.5°
Humidity: 39%
Current time: 08:30 PM
Sunrise: 06:52 AM
Sunset: 08:13 PM