2,100.45 mi Straight Distance
2,480.50 mi Driving Distance
1 day 23 hours Estimated Driving Time
The straight distance between Sandy Flat (New South Wales) and Jennapullin (Western Australia) is 2,100.45 mi, but the driving distance is 2,480.50 mi.
It takes to go from Sandy Flat to Jennapullin.
Driving directions from Sandy Flat to Jennapullin
Straight distance: 3,379.62 km. Route distance: 3,991.13 km
Latitude: -29.2312 // Longitude: 152.008

Forecast: Overcast clouds
Temperature: 18.5°
Humidity: 92%
Current time: 12:00 AM
Sunrise: 07:34 PM
Sunset: 08:36 AM
Latitude: -31.5341 // Longitude: 116.718

Forecast: Clear sky
Temperature: 20.5°
Humidity: 54%
Current time: 12:00 AM
Sunrise: 09:53 PM
Sunset: 11:00 AM