325.23 mi Straight Distance
440.90 mi Driving Distance
12 hours 16 mins Estimated Driving Time
The straight distance between Prospect (Tasmania) and Seymour (Victoria) is 325.23 mi, but the driving distance is 440.90 mi.
It takes to go from Prospect to Seymour.
Driving directions from Prospect to Seymour
Straight distance: 523.29 km. Route distance: 709.40 km
Latitude: -41.4704 // Longitude: 147.135

Forecast: Broken clouds
Temperature: 14.2°
Humidity: 82%
Current time: 03:51 AM
Sunrise: 06:50 AM
Sunset: 07:57 PM
Latitude: -37.0245 // Longitude: 145.137

Forecast: Overcast clouds
Temperature: 25.8°
Humidity: 61%
Current time: 03:51 AM
Sunrise: 07:03 AM
Sunset: 08:00 PM