Distance between 
Mount Prospect and 
Sebastopol
274.77 mi Straight Distance
341.47 mi Driving Distance
7 hours 7 mins Estimated Driving Time
The straight distance between Mount Prospect (Victoria) and Sebastopol (New South Wales) is 274.77 mi, but the driving distance is 341.47 mi.
It takes to go from Mount Prospect to Sebastopol.
Driving directions from Mount Prospect to Sebastopol
Distance in kilometers
Straight distance: 442.10 km. Route distance: 549.43 km
Mount Prospect, Australia
Latitude: -37.3892 // Longitude: 144.036
Photos of Mount Prospect
Mount Prospect Weather
Forecast: Clear sky
Temperature: 10.6°
Humidity: 85%
Current time: 12:00 AM
Sunrise: 08:03 PM
Sunset: 09:10 AM
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Light rain
Temperature: 20.6°
Humidity: 78%
Current time: 12:00 AM
Sunrise: 07:52 PM
Sunset: 08:53 AM
