Distance between 
Lascelles and 
Sebastopol
288.15 mi Straight Distance
377.65 mi Driving Distance
7 hours 31 mins Estimated Driving Time
The straight distance between Lascelles (Victoria) and Sebastopol (New South Wales) is 288.15 mi, but the driving distance is 377.65 mi.
It takes 7 hours 31 mins to go from Lascelles to Sebastopol.
Driving directions from Lascelles to Sebastopol
Distance in kilometers
Straight distance: 463.63 km. Route distance: 607.63 km
Lascelles, Australia
Latitude: -35.6085 // Longitude: 142.58
Photos of Lascelles
Lascelles Weather
Forecast: Clear sky
Temperature: 15.6°
Humidity: 76%
Sun info not available
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 17.8°
Humidity: 58%
Sun info not available
