2,100.45 mi Straight Distance
2,480.48 mi Driving Distance
1 day 23 hours Estimated Driving Time
The straight distance between Jennapullin (Western Australia) and Sandy Flat (New South Wales) is 2,100.45 mi, but the driving distance is 2,480.48 mi.
It takes to go from Jennapullin to Sandy Flat.
Driving directions from Jennapullin to Sandy Flat
Straight distance: 3,379.62 km. Route distance: 3,991.09 km
Latitude: -31.5341 // Longitude: 116.718

Forecast: Clear sky
Temperature: 34.5°
Humidity: 20%
Current time: 12:00 AM
Sunrise: 09:53 PM
Sunset: 11:00 AM
Latitude: -29.2312 // Longitude: 152.008

Forecast: Light rain
Temperature: 26.8°
Humidity: 47%
Current time: 12:00 AM
Sunrise: 07:34 PM
Sunset: 08:36 AM