713.93 mi Straight Distance
845.75 mi Driving Distance
17 hours 16 mins Estimated Driving Time
The straight distance between Gin Gin (Queensland) and Sebastopol (New South Wales) is 713.93 mi, but the driving distance is 845.75 mi.
It takes to go from Gin Gin to Sebastopol.
Driving directions from Gin Gin to Sebastopol
Straight distance: 1,148.71 km. Route distance: 1,360.81 km
Latitude: -24.9933 // Longitude: 151.96

Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 08:34 AM
Sunrise: 05:47 AM
Sunset: 06:20 PM
Latitude: -34.5851 // Longitude: 147.522

Forecast: Clear sky
Temperature: 18.0°
Humidity: 40%
Current time: 10:00 AM
Sunrise: 05:59 AM
Sunset: 06:43 PM