Distance between 
Chintin and 
Sebastopol
245.43 mi Straight Distance
294.38 mi Driving Distance
5 hours 46 mins Estimated Driving Time
The straight distance between Chintin (Victoria) and Sebastopol (New South Wales) is 245.43 mi, but the driving distance is 294.38 mi.
It takes 5 hours 46 mins to go from Chintin to Sebastopol.
Driving directions from Chintin to Sebastopol
Distance in kilometers
Straight distance: 394.89 km. Route distance: 473.66 km
Chintin, Australia
Latitude: -37.3978 // Longitude: 144.84
Photos of Chintin
Chintin Weather
Forecast: Overcast clouds
Temperature: 11.0°
Humidity: 69%
Sun info not available
Sebastopol, Australia
Latitude: -34.5851 // Longitude: 147.522
Photos of Sebastopol
Sebastopol Weather
Forecast: Clear sky
Temperature: 11.5°
Humidity: 63%
Sun info not available
